A logo design company purchases four new computers for $13,500. The company finances the cost of the computers for 3 years at an annual interest rate of 4.125% compounded monthly. Find the monthly payment (in dollars) for this loan. (Round your answer to the nearest cent. See Example 8 in this section.)
To calculate the monthly payment for the loan, we use the formula for the monthly payment of an amortized loan:
M=P⋅r⋅(1+r)n(1+r)n−1M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n – 1}M=(1+r)n−1P⋅r⋅(1+r)nWhere:
- MMM is the monthly payment,
- PPP is the loan amount (P=13,500P = 13,500P=13,500),
- rrr is the monthly interest rate (annual interest rate divided by 12),
- nnn is the total number of payments (number of years multiplied by 12).
Step 1: Assign values
- P=13,500P = 13,500P=13,500
- Annual interest rate = 4.125% = 0.04125
- Monthly interest rate r=0.0412512≈0.0034375r = \frac{0.04125}{12} \approx 0.0034375r=120.04125≈0.0034375
- Number of years = 3, so n=3×12=36n = 3 \times 12 = 36n=3×12=36.
Step 2: Substitute into the formula
M=13,500⋅0.0034375⋅(1+0.0034375)36(1+0.0034375)36−1M = \frac{13,500 \cdot 0.0034375 \cdot (1 + 0.0034375)^{36}}{(1 + 0.0034375)^{36} – 1}M=(1+0.0034375)36−113,500⋅0.0034375⋅(1+0.0034375)36Let me compute this.
The monthly payment for the loan is $399.32.
A logo design company purchases four new computers for $13,500. The company finances the cost of the computers for 3 years at an annual interest rate of 4.125% compounded monthly. Find the monthly payment (in dollars) for this loan. (Round your answer to the nearest cent. See Example 8 in this section.)
To calculate the monthly payment for the loan, we use the formula for the of an amortized loan:
M=P⋅r⋅(1+r)n(1+r)n−1M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n – 1}M=(1+r)n−1P⋅r⋅(1+r)nWhere:
- MMM is the
- PPP is the loan amount (P=13,500P = 13,500P=13,500),
- rrr is the monthly interest rate (annual interest rate divided by 12),
- nnn is the total number of payments (number of years multiplied by 12).
Step 1: Assign values
- P=13,500P = 13,500P=13,500
- Annual interest rate = 4.125% = 0.04125
- Monthly interest rate r=0.0412512≈0.0034375r = \frac{0.04125}{12} \approx 0.0034375r=120.04125≈0.0034375
- Number of years = 3, so n=3×12=36n = 3 \times 12 = 36n=3×12=36.
Step 2: Substitute into the formula
M=13,500⋅0.0034375⋅(1+0.0034375)36(1+0.0034375)36−1M = \frac{13,500 \cdot 0.0034375 \cdot (1 + 0.0034375)^{36}}{(1 + 0.0034375)^{36} – 1}M=(1+0.0034375)36−113,500⋅0.0034375⋅(1+0.0034375)36Let me compute this.