A logo design company purchases four new computers for $13,500. The company finances the cost of the computers for 3 years at an annual interest rate of 4.125% compounded monthly. Find the monthly payment (in dollars) for this loan. (Round your answer to the nearest cent. See Example 8 in this section.)

monthly payment for the loan

To calculate the monthly payment for the loan, we use the formula for the monthly payment of an amortized loan:

M=P⋅r⋅(1+r)n(1+r)n−1M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n – 1}Where:

  • MM is the monthly payment,
  • PP is the loan amount (P=13,500P = 13,500),
  • rr is the monthly interest rate (annual interest rate divided by 12),
  • nn is the total number of payments (number of years multiplied by 12).

Step 1: Assign values

  • P=13,500P = 13,500
  • Annual interest rate = 4.125% = 0.04125
  • Monthly interest rate r=0.0412512≈0.0034375r = \frac{0.04125}{12} \approx 0.0034375
  • Number of years = 3, so n=3×12=36n = 3 \times 12 = 36.

Step 2: Substitute into the formula

M=13,500⋅0.0034375⋅(1+0.0034375)36(1+0.0034375)36−1M = \frac{13,500 \cdot 0.0034375 \cdot (1 + 0.0034375)^{36}}{(1 + 0.0034375)^{36} – 1}Let me compute this.

The monthly payment for the loan is $399.32. ​

A logo design company purchases four new computers for $13,500. The company finances the cost of the computers for 3 years at an annual interest rate of 4.125% compounded monthly. Find the monthly payment (in dollars) for this loan. (Round your answer to the nearest cent. See Example 8 in this section.)

To calculate the monthly payment for the loan, we use the formula for the of an amortized loan:

M=P⋅r⋅(1+r)n(1+r)n−1M = \frac{P \cdot r \cdot (1 + r)^n}{(1 + r)^n – 1}Where:

  • MM is the
  • PP is the loan amount (P=13,500P = 13,500),
  • rr is the monthly interest rate (annual interest rate divided by 12),
  • nn is the total number of payments (number of years multiplied by 12).

Step 1: Assign values

  • P=13,500P = 13,500
  • Annual interest rate = 4.125% = 0.04125
  • Monthly interest rate r=0.0412512≈0.0034375r = \frac{0.04125}{12} \approx 0.0034375
  • Number of years = 3, so n=3×12=36n = 3 \times 12 = 36.

Step 2: Substitute into the formula

M=13,500⋅0.0034375⋅(1+0.0034375)36(1+0.0034375)36−1M = \frac{13,500 \cdot 0.0034375 \cdot (1 + 0.0034375)^{36}}{(1 + 0.0034375)^{36} – 1}Let me compute this.

The  is $399.32. ​

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